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产品型号JEM

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产品简介

江苏春晨电缆有限公司专业生产JEM电机引接线JEM电机绕组线JEM，变压器原理图单相变压器有两个线圈共同绕在一个闭合铁芯上，如右图所示，其中与电源相连的线圈称为原边线圈，与原边线圈相关的各量的标示符号均在右下角标注以角码

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江苏春晨电缆有限公司商铺

变压器工作原理
Working principle of transformer

变压器原理图单相变压器有两个线圈共同绕在一个闭合铁芯上，如右图所示，其中与电源相连的线圈称为原边线圈，与原边线圈相关的各量的标示符号均在右下角标注以角码1，如U1、I1等，与负载项链的线圈称为副边线圈，相关度额各量的标示符号均在右下角标注角码2，如U2、I2等。JEM电机引接线JEM电机绕组线JEM
The principle diagram of single-phase transformer transformer has two coil winding together in a closed iron core, as shown on the right, wherein the coil connected to the power source is called the primary coil, the symbol associated with the primary winding are marked in the lower right corner to corner 1, such as U1, I1, and negative coil load Necklace called secondary coil, symbol correlation value by weight are in the lower right corner marked corner 2, such as U2, I2 etc..
此变压器工作原理为：当变压器的原绕组施以交变电压u1时，便在原绕组中产生一个交变电流i1，这个电流在铁芯中产生交变磁通Φ，因为原、副绕组在同一个铁芯上，所以当磁通Φ穿过副绕组时，便在变压器副边产生感应电动势e2（即变压电压）。变压器中感应电动势的大小是和线圈的匝数、磁通的大小及电源的频率成正比。JEM电机引接线JEM电机绕组线JEM
This transformer working principle is: when the transformer primary winding with alternating voltage U1, will produce a I1 alternating current in primary winding, the current alternating flux in the core, because the primary and secondary windings on the same core, so when the flux through the secondary winding, will produce electromotive the potential E2 in the secondary side of the transformer (i.e. voltage transformer). The size of the induction electromotive force in the transformer is proportional to the number of turns, the size of the magnetic flux and the frequency of the power supply.
原副边电压计算
Primary side voltage calculation

变压器中感应电动势的计算公式为：
The calculation formula of induction electromotive force in the transformer is as follows:
变压器电动势计算
Calculation of transformer EMF
上面的公式中各量分表所指：
In the above formula, each quantity table refers to:
E：表示感应电动势，单位伏特，简称伏（V）；
E: the expression of induction electromotive force, unit volt (V);
f：表示电源频率，单位赫兹（Hz）；
F: the power frequency, unit Hertz (Hz);
N：表示线圈匝数（匝）；
N: the number of turns (turns);
Φ：表示磁通，单位韦伯（Wb）；
It is a magnetic flux, unit Webb (Wb);
由于磁通Φ穿过原、副边绕组而闭合，所以原、副边感应电动势分别为：
As the magnetic flux is closed through the primary and secondary winding, the primary and secondary induced electromotive force is:
变压器原边电动势计算公式
Calculation formula of primary side electromotive force of transformer
变压器副边电动势计算公式
Calculation formula of the EMF at the side of the transformer
两个公式相除得变压器变压比称为变压器的变比。
The two division was called the formula ratio of transformer transformer transformer.
变压器变压比
Transformer voltage ratio

在一般的电力变压器中，绕组电阻压降很小，可以忽略不计，因此在原边绕组中可以认为电压U1=E1。由于副边绕组开路，电流I2=0，它的端电压U2与感应电动势E2相等，即U2=E2。所以由上面的原、副边感应电动势公式得：
In the general power transformer, the voltage drop of the winding resistance is very small and can be ignored. Therefore, the voltage U1=E1 can be considered in the original side winding. Due to the open circuit of the secondary winding and the current I2=0, its end voltage U2 is equal to the induction electromotive force E2, that is, U2=E2. So from the above, the primary and secondary induced electromotive force formula:
变压器变压比
Transformer voltage ratio
公式中K为原边电压U1和副边电压U2之比，这个K的数值称为变压器的变压比。
In the formula, the K is the ratio of the original side voltage U1 to the secondary voltage U2, and the value of this K is called the transformer voltage ratio.
由上是表明，变压器原、副边绕组的电压比等于原、副绕组的匝数比，因此如果要原、副边绕组有不同的电压，只要改变他们的匝数即可。当N1＞N2时，K＞1，变压器降压；当N1＜N2时，K＜1，变压器升压。
It is shown that the voltage ratio of the primary and secondary winding of the transformer is equal to the ratio of the turns of the primary and secondary windings. Therefore, if the primary and secondary windings have different voltages, the number of turns must be changed. When N1 > N2, K > 1, transformer depressurization; when N1 < N2, K < 1, transformer booster.
对于已经支撑的变压器而言，其K为定值，故副边电压和原边电压成正比，也就是说副边电压随着原边电压的升高而升高，降低而降低。但加载原边绕组两端的电压必须为额定值。因为，当外加电压比额定电压略有超过时，原边绕组中通过的电流将大大增加，如果把额定电压为220V的变压器错误的接到380V的线路上，则原绕组的电流将急剧增大，致使变压器烧毁。
For a transformer that has been supported, its K is fixed, so the secondary voltage is directly proportional to the primary side voltage, that is to say, the secondary side voltage rises and decreases with the increase of the primary voltage. But the voltage at both ends of the original side winding must be rated. Because when the external voltage is slightly higher than the rated voltage, the current in the primary winding will increase greatly. If the transformer with a rated voltage of 220V is mistaken on the 380V line, the current of the original winding will increase sharply, causing the transformer to burn down.
把变压器的副边绕组负载接通后，在副边电路中有电流I2通过，此时，称变压器负载运行。由于副边绕组中电流I2也将在铁芯中产生磁通（即自感应现象），这种磁通对于原边电流所产生的磁通而言，是起去磁作用的，即铁芯中的磁通应为原边、副边绕组中电流产生的磁通的合成。但在外加电压U1和电源频率f不变的条件下，由近似公式：
After the load of the auxiliary side winding of the transformer is connected, the current I2 is passed in the secondary circuit. At this time, it is called the transformer load running. Because the current in the secondary winding of I2 will also be in the core of magnetic flux (i.e. self induction), the magnetic flux produced by the primary current, is go to the magnetic field, the magnetic flux in the core that the synthesis flux should be generated for the primary current and secondary winding in the. But under the condition of the constant voltage U1 and the power frequency f, the approximate formula:
原边电压
Primary side voltage
上式中可以看出，合成磁通Φ应基本保持不变。因此，随着I2出现，原边绕组中通过的电流I1将增加，这样才能使得原绕组中的磁通以免体校副绕组的磁通，另一面维持铁芯中的合成磁通保持不变。由此可知，变压器原边电流I1的大小是由副边电流I2的大小来决定的。
As can be seen in the upper formula, the synthetic magnetic flux diameter should be basically kept unchanged. Therefore, with the advent of I2, the current I1 in the primary winding will increase, so that the magnetic flux in the original winding will not be allowed to avoid the flux of secondary windings in the secondary school, and the synthetic flux in the core will remain unchanged on the other side. It can be seen that the size of the original current I1 of the transformer is determined by the size of the secondary current I2.
从能量观点来看，变压器原边线圈从电源吸取的功率P1应等于副边线圈的输出功率P2（忽略变压器的线圈电阻和磁通的传递损耗），即：
From the energy point of view, the power P1 of the primary coil of the transformer from the power source should be equal to the output power P2 of the secondary side coil (neglecting the coil resistance and the transmission loss of the magnetic flux).
P1=P2 或 I1U1=I2U2
P1=P2 or I1U1=I2U2
所以变压比：
So the pressure change ratio:
变压器变压比
Transformer voltage ratio
由此可见，变压器原边、副边的电流比与他们的匝数比或电压比成反比。例如一台变压器的匝数N1＜N2，是升压变压器，则电流I1＞I2；如果绕组匝数N1＞N2为降压变压器，则电流I2＞I1。也就是说，电压高的一边电流小，而电压低的一边电流大。
It can be seen that the current ratio of the primary and secondary sides of the transformer is inversely proportional to the ratio of their turn to turn or the voltage ratio. For example, the turn number of a transformer is N1 < N2, is a boost transformer, then the current I1 > I2; if the number of winding turns is N1 > N2 as the step-down transformer, then the current I2 > I1. That is to say, the side current of high voltage is small and the side current of low voltage is large.